# DERIVATIVE APPLICATION EXERCISE

DERIVATIVE APPLICATION EXERCISE

Calculate the Y values corresponding to the X values given below.  Find the critical values for X for the given polynomial by finding the X values among those given where the first derivative, dy/dx = 0 and/or X values where the second derivative, d2y/dx2 = 0.    Be sure to find the sign (+ or -) of  dy/dx and of d2y/dx2 at all X values. Reference Lesson 13 and the text Appendix A (pp 694 – 698), as needed.  Using the first and second derivative tests with the information you have calculated, determine which X value(s) represent maximums (MAX), which minimums (MIN) and which inflection points (INF).  Label the qualifying X value as such.  Attach work to convince me you carried out these calculations.  An Excel spreadsheet can make calculations easier.  If used, please attach the spreadsheet file and upload it with the rest of your work so that I can examine your formulas.  The beginning and ending X values below are not to be considered critical values.  In the space after the “Bonus Opportunity” write the first derivative (dy/dx) and the second derivative (d2y/dx2) you used or you will not receive credit for them.

Y = X3 -5X2 -8X +20

 X -1.333 -.667 0 1 1.667 3 4 5 Y dy/dx d2y/dx2 Label Point (MAX, MIN, INF)

Twenty point Bonus Opportunity (creditable toward the maximum of 600 exercise points).  Use the eight X values and their Y values you found above (which include the critical values) to help neatly sketch the graph of this polynomial function over the range of X values given.   Alternatively use a spreadsheet to plot it.  Your sketch must be consistent with the tabled values above (which means, if you claim a certain X value is a maximum, then the graph of it should show this same value as a maximum.  Similarly, if you claim an X value is an inflection point, then the graph of it should show it to be so.  A minimum should graph as a minimum, too.  The point is, if you figure out how the derivatives SIGNAL which X values are critical points, the graph of the values should show them as such.)

Here’s the SOLUTION

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